How to create a faulty calculator on Python using IfElse?

Code for faulty calculator whose outcomes will be wrong on these conditions and true results for other calculations using IfElse Statement:

55+6=77

56-4=7

45*3=77 and

56/6=4

inp = input("Enter a Operator you want to use"
            "+,-,*,/\n")
a = int(input("Enter first number: "))
b = int(input("Enter Second number: "))
if inp=='+':
    if a==56 and b==6:
        print("Sum is 77")
    else:
        print("Sum is", int(a) + int(b))
if inp=='-':
    if a==56 and b==4:
        print("Difference is 7")
    else:
        print("Difference is", int(a) - int(b))

if inp=='*':
    if a==45 and b==3:
        print("Product is 77")
    else:
        print("Product is", int(a) * int(b))
if inp=='/':
    if a==56 and b==6:
        print("Division is 4")
    else:
        print("Division is", int(a) / int(b))
else:
    print("Enter a valid Operator")

Output for other calculations:

Output for given faulty calculations: